100 mL of is mixed with 100 mL of . The molarity of in the resulting final solution is: β Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
100 mL of $0.5 \text{ M } NaOH$ is mixed with 100 mL of $0.5 \text{ M } H_2SO_4$. The molarity of $H_2SO_4$ in the resulting final solution is:
Answer: B
π‘ Solution & Explanation
$\text{mmol } NaOH = 50$, $\text{mmol } H_2SO_4 = 50$. $2NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O$. 50 mmol $NaOH$ reacts with 25 mmol $H_2SO_4$. Remaining $H_2SO_4 = 25 \text{ mmol}$. $\text{Molarity} = 25 / 200 = 0.125 \text{ M}$.
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