What volume of this acid is required to prepare of ? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$M_1V_1 = M_2V_2 \Rightarrow 18.4 \times V_1 = 0.5 \times 2000 \Rightarrow V_1 = 1000 / 18.4 \approx 54.35\text{ mL}$.