**Statement-1:** The equivalent weight of in acidic medium is . <br>**Statement-2:** In acidic mediu — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Statement-1:** The equivalent weight of $KMnO_4$ in acidic medium is $M/5$. <br>**Statement-2:** In acidic medium, $Mn^{7+}$ is reduced to $Mn^{2+}$.
Answer: A
💡 Solution & Explanation
In acidic medium, $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$. The change in oxidation state is 5, so $\text{Eq. wt} = \text{Molar mass} / 5$. Statement-2 correctly explains the n-factor.
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