The mole ratio of to in the original mixture is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The mole ratio of $H_2C_2O_4$ to $NaHC_2O_4$ in the original mixture is:
Answer: C
💡 Solution & Explanation
Let moles of $H_2C_2O_4$ be $x$ and $NaHC_2O_4$ be $y$. <br>Acid-Base: $2x + y = \text{mEq NaOH} \times 10$. <br>Redox: $2x + 2y = \text{mEq } KMnO_4 \times 10$. <br>Solving the equations yields $x=y$. [1]
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