of a hydrocarbon requires of and produces of . The formula is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$10 \text{ mL}$ of a hydrocarbon $C_xH_y$ requires $55 \text{ mL}$ of $O_2$ and produces $40 \text{ mL}$ of $CO_2$. The formula is:
Answer: A
💡 Solution & Explanation
$x = V_{CO_2} / V_{HC} = 40/10 = 4$. <br>$x + y/4 = V_{O_2} / V_{HC} = 5.5 \Rightarrow 4 + y/4 = 5.5 \Rightarrow y/4 = 1.5 \Rightarrow y = 6$. <br>Formula $C_4H_6$.
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