of a mixture of and yields of on treatment with . The percentage of in mixture is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{moles } Cl = \text{moles } AgCl = 2.3 / 143.5 \approx 0.016$. <br>Let $x$ be mass of $MgCl_2$ (MW=95). $2x/95 + (1-x)/58.5 = 0.016$. <br>Solving gives $x \approx 0.475 \text{ g} \Rightarrow 47.5\%$.