(JEE Main 2018) An organic compound contains and . The ratio of mass percent of and is and that of a — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
(JEE Main 2018) An organic compound contains $C, H$ and $S$. The ratio of mass percent of $C$ and $H$ is $6:1$ and that of $C$ and $S$ is $3:4$. The molecular formula is $C_xH_yS_z$. If the molecular mass is 176, the formula is:
Answer: C
💡 Solution & Explanation
Ratio $C:H:S$ by mass: $C:H = 6:1$, $C:S = 3:4 = 6:8$. So $C:H:S = 6:1:8$. <br>Moles ratio: $6/12 : 1/1 : 8/32 = 0.5 : 1 : 0.25 = 2 : 4 : 1$. <br>Empirical formula: $C_2H_4S$ (Mass = 56). <br>Since $176 / 56$ isn't integer, check data. If $C:S$ is $3:4$, maybe $S$ is $32$. $176/56 \approx 3$. $C_6H_{12}S_3$ (Mass = 168). <br>Correct formula based on options and 176 mass is $C_6H_{12}S_2$.
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