Boron has two stable isotopes, (19%) and (81%). The average atomic weight of Boron is: | Mole Concept and Some Basic Concepts of Chemistry — Chem-Mantra

Question

Boron has two stable isotopes, $^{10}B$ (19%) and $^{11}B$ (81%). The average atomic weight of Boron is:

Answer: A

💡 Solution & Explanation

$\text{Avg. mass} = (10 \times 0.19) + (11 \times 0.81) = 1.9 + 8.91 = 10.81$.

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