of is mixed with of . The resulting molarity of ions in the solution is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$100 \text{ mL}$ of $0.1 \text{ M } H_2SO_4$ is mixed with $100 \text{ mL}$ of $0.1 \text{ M } NaOH$. The resulting molarity of $H^+$ ions in the solution is:
Answer: A
💡 Solution & Explanation
$\text{moles } H^+ = 100 \times 0.1 \times 2 = 20 \text{ mmol}$. <br>$\text{moles } OH^- = 100 \times 0.1 \times 1 = 10 \text{ mmol}$. <br>$\text{Remaining } H^+ = 10 \text{ mmol}$. <br>$\text{Total volume} = 200 \text{ mL}$. <br>$\text{Molarity} = 10 / 200 = 0.05 \text{ M}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes