is mixed with . The maximum number of moles of that can be formed is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$0.5 \text{ mol } BaCl_2$ is mixed with $0.2 \text{ mol } Na_3PO_4$. The maximum number of moles of $Ba_3(PO_4)_2$ that can be formed is:
Answer: A
💡 Solution & Explanation
$3BaCl_2 + 2Na_3PO_4 \rightarrow Ba_3(PO_4)_2 + 6NaCl$. <br>$\text{Ratio } BaCl_2 : Na_3PO_4 = 3:2$. <br>Required $BaCl_2$ for $0.2 \text{ mol } Na_3PO_4 = (3/2) \times 0.2 = 0.3$. <br>We have 0.5, so $Na_3PO_4$ is limiting. <br>$\text{Moles } Ba_3(PO_4)_2 = 0.2 / 2 = 0.1 \text{ mol}$.
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