The density of a solution of is . The molality of the solution is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The density of a $1 \text{ M}$ solution of $Na_2CO_3$ is $1.1 \text{ g/mL}$. The molality of the solution is:
Answer: A
💡 Solution & Explanation
$\text{Mass of 1 L solution} = 1100 \text{ g}$. <br>$\text{Mass of solute (MW=106)} = 106 \text{ g}$. <br>$\text{Mass of solvent} = 1100 - 106 = 994 \text{ g} = 0.994 \text{ kg}$. <br>$\text{Molality} = 1 / 0.994 \approx 1.006 \text{ m}$. (Closest is 1.058 or 1.00 depending on rounding).
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes