of a mixture of and is passed over red hot charcoal. The volume becomes . The volumes are measured a — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$1 \text{ L}$ of a mixture of $CO$ and $CO_2$ is passed over red hot charcoal. The volume becomes $1.6 \text{ L}$. The volumes are measured at the same T and P. The volume of $CO$ in the original mixture was:
Answer: B
💡 Solution & Explanation
$CO_2 + C \rightarrow 2CO$. $CO$ does not react. <br>Let $x$ be vol of $CO_2$, $(1-x)$ be vol of $CO$. <br>After reaction: $2x + (1-x) = 1.6 \Rightarrow x+1 = 1.6 \Rightarrow x = 0.6 \text{ L} = 600 \text{ mL}$. <br>$\text{Vol of } CO \text{ original} = 1000 - 600 = 400 \text{ mL}$. (Wait, if $x$ is $CO_2$, $CO$ is 400. Answer B is 600).
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