of are reacted with of . The volume of produced at STP is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$4 \text{ moles}$ of $MgCO_3$ are reacted with $6 \text{ moles}$ of $HCl$. The volume of $CO_2$ produced at STP is:
Answer: A
💡 Solution & Explanation
$MgCO_3 + 2HCl \rightarrow MgCl_2 + H_2O + CO_2$. <br>Ratio $1:2$. For 4 mol $MgCO_3$, 8 mol $HCl$ needed. <br>We have 6 mol $HCl$ (Limiting). <br>Moles $CO_2 = 6 / 2 = 3 \text{ mol}$. <br>Volume $= 3 \times 22.4 = 67.2 \text{ L}$. [1, 10]
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