A sample of contains 6.4 moles of oxygen atoms. The number of moles of ions in the sample is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
A sample of $K_2SO_4 \cdot Al_2(SO_4)_3 \cdot 24H_2O$ contains 6.4 moles of oxygen atoms. The number of moles of $Al^{3+}$ ions in the sample is:
Answer: B
💡 Solution & Explanation
Total O atoms in formula: $4 + 3(4) + 24 = 40$. <br>Ratio $Al^{3+} : O = 2 : 40 = 1 : 20$. <br>Moles $Al^{3+} = 6.4 / 20 = 0.32$. (Wait, recalculating: $4+12+24=40$. $6.4/40 = 0.16$. $0.16 \times 2 = 0.32$). If options are as provided, please check PDF for $SO_4$ count. If it's $Al_2(SO_4)_3$, the ratio is $2:40$. [1]
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