(JEE Main 2013) A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of . The empi — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Moles of $C = \text{moles of } CO_2 = 3.08 / 44 = 0.07$. <br>Moles of $H = 2 \times \text{moles of } H_2O = 2 \times (0.72 / 18) = 0.08$. <br>Ratio $C:H = 7:8$. Empirical formula is $C_7H_8$. [1, 8]