(AIEEE 2012) The density of a solution of is . The molality of the solution is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
(AIEEE 2012) The density of a $3\text{ M}$ solution of $NaCl$ is $1.25 \text{ g mL}^{-1}$. The molality of the solution is:
Answer: A
💡 Solution & Explanation
Mass of 1L solution $= 1250 \text{ g}$. <br>Mass of $NaCl = 3 \times 58.5 = 175.5 \text{ g}$. <br>Mass of solvent $= 1250 - 175.5 = 1074.5 \text{ g} = 1.0745 \text{ kg}$. <br>Molality $= 3 / 1.0745 \approx 2.79 \text{ m}$. [1]
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