(AIEEE 2003) Two solutions of a substance (non-electrolyte) are mixed in the following manner: of of — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
(AIEEE 2003) Two solutions of a substance (non-electrolyte) are mixed in the following manner: $480\text{ mL}$ of $1.5\text{ M}$ of first solution $+ 520\text{ mL}$ of $1.2\text{ M}$ of second solution. What is the molarity of final mixture?
Answer: C
💡 Solution & Explanation
$M_{final} = (M_1V_1 + M_2V_2) / (V_1 + V_2) = (1.5 \times 480 + 1.2 \times 520) / 1000 = (720 + 624) / 1000 = 1.344\text{ M}$. [20, 32]
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes