The molarity of a solution of is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{Molarity} = \text{Normality} / \text{n-factor}$. <br>For $Na_2CO_3$, $\text{n-factor (total cationic charge)} = 2$. <br>$M = 0.2 / 2 = 0.1\text{ M}$. [9, 10]