of an impure sample of magnesium carbonate is reacted with to give of . The percentage purity of the — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$MgCO_3 + 2HCl \rightarrow MgCl_2 + H_2O + CO_2$. <br>$\text{Moles } CO_2 = 2.2 / 44 = 0.05$. $\text{Moles } MgCO_3 = 0.05$. <br>$\text{Mass } MgCO_3 = 0.05 \times 84 = 4.2\text{ g}$. $\% \text{ purity} = (4.2 / 10) \times 100 = 42\%$.