Volume of required to neutralize of is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
Volume of $0.6\text{ M } NaOH$ required to neutralize $30\text{ mL}$ of $0.4\text{ M } HCl$ is:
Answer: A
💡 Solution & Explanation
$M_1V_1 = M_2V_2 \Rightarrow 0.6 \times V = 0.4 \times 30 \Rightarrow 0.6V = 12 \Rightarrow V = 20\text{ mL}$.
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