Volume of required to neutralize of is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$M_1V_1 = M_2V_2 \Rightarrow 0.6 \times V = 0.4 \times 30 \Rightarrow 0.6V = 12 \Rightarrow V = 20\text{ mL}$.