The percentage of copper in is: (At. wt. ) β Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The percentage of copper in $CuSO_4 \cdot 5H_2O$ is: (At. wt. $Cu=63.5, S=32, O=16, H=1$)
Answer: A
π‘ Solution & Explanation
$\text{Molar mass} = 63.5 + 32 + 64 + 90 = 249.5\text{ g/mol}$. <br>$\% Cu = (63.5 / 249.5) \times 100 \approx 25.4\%$.
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