of and of were dissolved in water to have of solution. The molarity of ions is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$0.2\text{ mole}$ of $HCl$ and $0.1\text{ mole}$ of $CaCl_2$ were dissolved in water to have $500\text{ mL}$ of solution. The molarity of $Cl^-$ ions is:
Answer: B
💡 Solution & Explanation
$\text{Moles of } Cl^- \text{ from } HCl = 0.2$. <br>$\text{Moles of } Cl^- \text{ from } CaCl_2 = 2 \times 0.1 = 0.2$. <br>$\text{Total moles} = 0.4$. $\text{Molarity} = 0.4 / 0.5 = 0.8\text{ M}$.
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