of solution is electrolyzed and of is deposited. The molarity of the remaining solution is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$500\text{ mL}$ of $0.1\text{ M } CuSO_4$ solution is electrolyzed and $0.01\text{ mole}$ of $Cu$ is deposited. The molarity of the remaining solution is:
Answer: B
💡 Solution & Explanation
$\text{Initial moles} = 0.5 \times 0.1 = 0.05$. $\text{Moles left} = 0.05 - 0.01 = 0.04$. <br>$\text{Molarity} = 0.04 / 0.5 = 0.08\text{ M}$.
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