How many grams of can be prepared from of phosphorus? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$P \rightarrow H_3PO_4$. By POAC on P: $\text{moles of } P = \text{moles of } H_3PO_4$. <br>$\text{Moles of } P = 6.2 / 31 = 0.2$. <br>$\text{Mass of } H_3PO_4 = 0.2 \times 98 = 19.6\text{ g}$.