For the reaction , when and are mixed, the limiting reagent is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{Req. ratio: } A:B:C = 2:3:4$. <br>For $0.6\text{ mol } B$, we need $(2/3) \times 0.6 = 0.4\text{ mol } A$ and $(4/3) \times 0.6 = 0.8\text{ mol } C$. <br>We have $1.2\text{ mol } A$ (excess) and $0.75\text{ mol } C$ (deficient). <br>Wait, let's check $C$: For $0.75\text{ mol } C$, we need $(3/4) \times 0.75 = 0.56\text{ mol } B$. We have $0.6\text{ mol } B$. <br>So $C$ is the limiting reagent. Correct Answer: C.