A solution is prepared by dissolving of in of a solvent of density . The molality of the solution is — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
A solution is prepared by dissolving $10\text{ g}$ of $NaOH$ in $1250\text{ mL}$ of a solvent of density $0.8\text{ g/mL}$. The molality of the solution is:
Answer: A
💡 Solution & Explanation
$\text{Mass of solvent} = 1250 \times 0.8 = 1000\text{ g} = 1\text{ kg}$. $\text{Moles of } NaOH = 10/40 = 0.25$. $\text{Molality} = 0.25 / 1 = 0.25\text{ m}$.
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