How many liters of oxygen (at STP) are required to burn 60 g of completely? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O$. <br>$\text{Moles } C_2H_6 = 60/30 = 2$ mol. <br>$\text{Moles } O_2 \text{ needed} = 7/2 \times 2 = 7$ mol. <br>$\text{Volume} = 7 \times 22.4 = 156.8 \text{ L}$.