0.24 g of a volatile liquid on vaporization gives 45 mL of vapour at STP. The molecular weight of the liquid is: | Mole Concept and Some Basic Concepts of Chemistry — Chem-Mantra

Question

0.24 g of a volatile liquid on vaporization gives 45 mL of vapour at STP. The molecular weight of the liquid is:

Answer: B

💡 Solution & Explanation

$\text{Moles} = \text{Volume}/22400 = 45 / 22400 \approx 0.002009$ mol. <br>$\text{MW} = \text{Mass}/\text{Moles} = 0.24 / 0.002009 \approx 119.46$.

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