Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is : — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{Mass of 1L solution} = 1020 \text{ g}$. <br>$\text{Mass of solute (acetic acid, MW=60)} = 2.05 \times 60 = 123 \text{ g}$. <br>$\text{Mass of solvent} = 1020 - 123 = 897 \text{ g} = 0.897 \text{ kg}$. <br>$\text{Molality} = 2.05 / 0.897 \approx 2.28 \text{ m}$.