Number of protons, neutrons and electrons in 7 mg of ion is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
Number of protons, neutrons and electrons in 7 mg of $^{14}C^{4-}$ ion is:
Answer: B
💡 Solution & Explanation
$\text{Moles} = 7 \times 10^{-3} / 14 = 5 \times 10^{-4}$ mol. <br>$\text{Number of ions} = 5 \times 10^{-4} \times 6 \times 10^{23} = 3 \times 10^{20}$. <br>Wait, calculating with $N_A = 6.02 \times 10^{23}$: <br>Protons per ion = 6. Total $= 1.8 \times 10^{21}$. <br>Neutrons per ion = $14 - 6 = 8$. Total $= 2.4 \times 10^{21}$. <br>Electrons per ion = $6 + 4 = 10$. Total $= 3 \times 10^{21}$.
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