The number of moles of Mohr's salt that contain 4.8 g of oxygen atoms is : — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The number of moles of Mohr's salt $[FeSO_4 \cdot (NH_4)_2SO_4 \cdot 6H_2O]$ that contain 4.8 g of oxygen atoms is :
Answer: B
💡 Solution & Explanation
Total Oxygen atoms in Mohr's salt formula: $4 (SO_4) + 4 (SO_4) + 6 (H_2O) = 14$ Oxygen atoms. <br>Moles of O atoms $= 4.8 / 16 = 0.3$ mol. <br>$\text{Moles of compound} = \text{moles of O} / 14 = 0.3 / 14 \approx 0.021$ mol. Closest option is 0.02.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes