If 0.50 mol of is mixed with 0.20 mol of , the maximum number of moles of which can be formed, is: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Reaction: $3CaCl_2 + 2Na_3PO_4 \rightarrow Ca_3(PO_4)_2 + 6NaCl$. <br>Moles $CaCl_2$ needed for 0.20 mol $Na_3PO_4 = (3/2) \times 0.2 = 0.3$. We have 0.5, so $Na_3PO_4$ is limiting. <br>Moles $Ca_3(PO_4)_2 = 0.2 / 2 = 0.1$ mol.