How many grams of are required to neutralize 852 g of ? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$6CaO + P_4O_{10} \rightarrow 2Ca_3(PO_4)_2$. $\text{Moles } P_4O_{10} = 852/284 = 3$. $\text{Moles } CaO = 6 \times 3 = 18$. $\text{Mass } CaO = 18 \times 56 = 1008 \text{ g}$. [7]