Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4). Then minimum mol — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is:
Answer: A
💡 Solution & Explanation
$\text{Min. MW} = (\text{At. wt.} \times 100) / \% = (78.4 \times 100) / 0.5 = 15680 = 1.568 \times 10^4$. [3]
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