If is Avogadro's number, then number of valence electrons in 4.2 g of ions is: | Mole Concept and Some Basic Concepts of Chemistry — Chem-Mantra

Question

If $N_A$ is Avogadro's number, then number of valence electrons in 4.2 g of $N^{3-}$ ions is:

Answer: A

💡 Solution & Explanation

$\text{Moles} = 4.2/14 = 0.3$. $N^{3-}$ has $5+3=8$ valence electrons. $\text{Total} = 0.3 \times 8 \times N_A = 2.4 N_A$. [2]

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