molecules are removed from 200 mg of . The moles of left are : — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$10^{21}$ molecules are removed from 200 mg of $CO_2$. The moles of $CO_2$ left are :
Answer: A
💡 Solution & Explanation
$\text{Initial moles} = 0.2/44 = 0.00454$. $\text{Moles removed} = 10^{21} / (6.022 \times 10^{23}) = 0.00166$. $\text{Remaining moles} = 0.00454 - 0.00166 = 0.00288$. [1]
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