molecules are removed from 200 mg of . The moles of left are : [1] — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Initial moles $= \frac{0.2 \text{ g}}{44 \text{ g/mol}} = 0.004545$ mol. <br>Moles removed $= \frac{10^{21}}{6.022 \times 10^{23}} = 0.001660$ mol. <br>Moles left $= 0.004545 - 0.001660 = 0.002885$ mol $\approx 2.88 \times 10^{-3}$ mol. [1]