For a aqueous solution of (density ), which is/are correct? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
For a $1\text{ M}$ aqueous solution of $NaOH$ (density $= 1.04\text{ g/mL}$), which is/are correct?
Answer: A,B,C
💡 Solution & Explanation
$\text{Mass of 1 L solution} = 1040 \text{ g}$. $\text{Mass of solute } (NaOH) = 1 \times 40 = 40 \text{ g}$. $\text{Mass of solvent} = 1040 - 40 = 1000 \text{ g} = 1 \text{ kg}$. $\text{Molality} = 1 \text{ mole} / 1 \text{ kg} = 1 \text{ m}$.
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