For a aqueous solution of (density ), which is/are correct? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{Mass of 1 L solution} = 1040 \text{ g}$. $\text{Mass of solute } (NaOH) = 1 \times 40 = 40 \text{ g}$. $\text{Mass of solvent} = 1040 - 40 = 1000 \text{ g} = 1 \text{ kg}$. $\text{Molality} = 1 \text{ mole} / 1 \text{ kg} = 1 \text{ m}$.