In a mixture of and having average molecular weight 34: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
In a mixture of $CO$ and $CO_2$ having average molecular weight 34:
Answer: B,C,D
💡 Solution & Explanation
$34 = 28x + 44(1-x) \Rightarrow 34 = 28x + 44 - 44x \Rightarrow 16x = 10 \Rightarrow x = 0.625$ (mole fraction of $CO$). <br>$\chi_{CO_2} = 0.375$. Ratio $= 0.625/0.375 \approx 1.66$. <br>Since $x > 0.5$, $CO$ has more moles/volume. <br>Mass ratio $= (0.625 \times 28) : (0.375 \times 44) = 17.5 : 16.5$. $CO$ is more by mass too.
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