(JEE Advanced 2013) The mole fraction of a solute in a solution is 0.1. At , molarity of this soluti — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
(JEE Advanced 2013) The mole fraction of a solute in a solution is 0.1. At $298 \text{ K}$, molarity of this solution is the same as its molality. If this solution has density $2.0 \text{ g/cm}^3$, then the ratio of molar mass of solute to molar mass of solvent is:
Answer: A
💡 Solution & Explanation
If $M=m$, then $d = 1 + M \times M_1 / 1000$ (where $M_1$ is solute MW). Using $\chi = 0.1$ and $d=2$, the calculation leads to $M_{solute}/M_{solvent} = 9$.
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