In 100 mL of solution: — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
In 100 mL of $0.1 \text{ M } Na_2SO_4$ solution:
Answer: A,B,C,D
💡 Solution & Explanation
$\text{Moles } Na_2SO_4 = 0.1 \text{ L} \times 0.1 \text{ M} = 0.01$. <br>Each unit gives $2 Na^+$ and $1 SO_4^{2-}$. <br>$\text{Moles } Na^+ = 2 \times 0.01 = 0.02$; $\text{Moles } SO_4^{2-} = 0.01$. <br>$[Na^+] = 0.02 \text{ mol} / 0.1 \text{ L} = 0.2 \text{ M}$.
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