The molarity of in a solution containing and in is . Find . — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The molarity of $Cl^-$ in a solution containing $0.1\text{ mole } NaCl$ and $0.1\text{ mole } CaCl_2$ in $500 \text{ mL}$ is $x \text{ M}$. Find $x$.
Answer: 0.6
💡 Solution & Explanation
$\text{moles } Cl^- = 0.1(NaCl) + 2 \times 0.1(CaCl_2) = 0.3 \text{ mol}$. <br>$\text{Molarity} = 0.3 \text{ mol} / 0.5 \text{ L} = 0.6 \text{ M}$.
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