of is mixed with of . What is the molarity of in the final solution? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$100 \text{ mL}$ of $0.1 \text{ M } H_2SO_4$ is mixed with $400 \text{ mL}$ of $0.05 \text{ M } NaOH$. What is the molarity of $Na_2SO_4$ in the final solution?
Answer: 0.02
💡 Solution & Explanation
$\text{moles } H_2SO_4 = 0.01$; $\text{moles } NaOH = 0.02$. <br>Reaction: $H_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O$. <br>Both react completely. $\text{moles } Na_2SO_4 = 0.01$. <br>$\text{Total volume} = 500 \text{ mL}$. <br>$\text{Molarity} = 0.01 / 0.5 = 0.02 \text{ M}$.
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