Mole Concept and Some Basic Concepts of ChemistrymediumINTEGER

The density of is . Calculate the mole fraction of .Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

Question

The density of $3 \text{ M } Na_2S_2O_3$ is $1.25 \text{ g/mL}$. Calculate the mole fraction of $Na_2S_2O_3$.

Answer: 0.065

💡 Solution & Explanation

$\text{Mass of 1 L} = 1250 \text{ g}$. $\text{Solute} = 3 \times 158 = 474 \text{ g}$. <br>$\text{Solvent} = 1250 - 474 = 776 \text{ g}$. <br>$\text{moles water} = 776 / 18 = 43.11 \text{ mol}$. <br>$\chi = \frac{3}{3 + 43.11} \approx 0.065$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry