How many grams of are required to oxidize of in acidic medium? (MW of salt = 278) — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
How many grams of $KMnO_4$ are required to oxidize $5.56 \text{ g}$ of $FeSO_4 \cdot 7H_2O$ in acidic medium? (MW of salt = 278)
Answer: 0.632
💡 Solution & Explanation
$\text{moles } Fe^{2+} = \frac{5.56}{278} = 0.02 \text{ mol}$. <br>Ratio $KMnO_4 : Fe^{2+} = 1 : 5$. <br>$\text{moles } KMnO_4 = 0.004 \text{ mol}$. <br>$\text{Mass} = 0.004 \times 158 = 0.632 \text{ g}$.
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