What is the n-factor of when it is oxidized to and ? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
What is the n-factor of $FeC_2O_4$ when it is oxidized to $Fe^{3+}$ and $CO_2$?
Answer: 3
💡 Solution & Explanation
$Fe^{2+} \rightarrow Fe^{3+} + e^-$ ($1 e^-$). <br>$C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-$ ($2 e^-$). <br>$\text{Total electrons lost} = 1 + 2 = 3$. <br>Thus, the n-factor is 3.
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