How many grams of are required to prepare of solution? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{Moles} = M \times V(L) = 0.1 \times 0.5 = 0.05 \text{ mol}$. <br>$\text{Mass} = 0.05 \times 40 = 2 \text{ g}$.