Find the total number of valence electrons in of azide ion () in units of . — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{moles } N_3^- = 4.2 / 42 = 0.1$. <br>Valence $e^-$ per $N_3^- = 3(5) + 1 = 16$. <br>Total valence electrons $= 0.1 \times 16 \times N_A = 1.6 N_A$. [11, 28]