A certain amount of a metal (at. wt. 27) reacted with excess acid to produce of at STP. What mass of — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
A certain amount of a metal $M$ (at. wt. 27) reacted with excess acid to produce $3.36 \text{ L}$ of $H_2$ at STP. What mass of metal was used (in grams)?
Answer: 2.7
💡 Solution & Explanation
Metal is trivalent ($Al$). $2M + 6H^+ \rightarrow 2M^{3+} + 3H_2$. <br>$\text{moles } H_2 = 3.36 / 22.4 = 0.15$. <br>$\text{moles } M = (2/3) \times 0.15 = 0.1$. <br>$\text{Mass} = 0.1 \times 27 = 2.7 \text{ g}$. [4, 26]
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