The density of solution of is . The molality of the solution is . Find . — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The density of $1\text{M}$ solution of $NaCl$ is $1.0585 \text{ g/mL}$. The molality of the solution is $x$. Find $x$.
Answer: 1
💡 Solution & Explanation
$\text{Mass of 1L solution} = 1058.5 \text{ g}$. <br>$\text{Mass of solute } (NaCl) = 1 \times 58.5 = 58.5 \text{ g}$. <br>$\text{Mass of solvent} = 1058.5 - 58.5 = 1000 \text{ g} = 1 \text{ kg}$. <br>$\text{Molality} = 1 \text{ mol} / 1 \text{ kg} = 1 \text{ m}$. [2, 7]
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